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How to find Equation of a Circle by its center and radius (e.g 1)

How to find the Equation of a Circle if the coordinates of its center and the length of its radius are given.

Click here for EXAMPLE 2

EXAMPLE 1: What is the equation of a circle whose center is at (-5, -8) and radius is 11 units long?

SOLUTION: 

A detailed discussed Example No: 1 on how to find the Equation of a Circle if the coordinates of its center and the length of its radius are given.

The standard equation of a circle is given by:

(x – h)² + (y – k)² = r² ————————(1)

Where (h, k) is the coordinates of center of the circle and r is the radius of the circle.

 

In this question, circle center is at (-5, -8)

So,

(h , k) = ( -5, -8)

which implies

h = -5

k = -8

 

Its radius is 11. So,

r = 11

 

Put these values in equation (1)

(x – h)² + (y – k)² = r²

{x – (-5) }² + { y – (-8) }² = 11²

 

{x + 5 }² + { y + 8 }² = 121

 

This is the standard equation of the circle whose center is at (-5, -8) and radius is 11 units long.

 

This standard equation can be written as general equation (or simply an equation) of a circle whose center is at (-5, -8) and radius is 11 units long by squaring the terms, then simplifying.

 

{x + 5 }² + { y + 8 }² = 121

 

{x² + 25 + 10x} + { y² + 64 + 16y } = 121

 

x² + y² +10x + 16y + 25 + 64 – 121 = 0

 

x² + y² +10x + 16y – 32 = 0

 

This is the general equation (or simply an equation) of a circle whose center is at (-5, -8) and radius is 11 units long.

 

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